-0.01x^2-0.2x+8=6

Solution for -0.01x^2-0.2x+8=6 equation:

-0.01x^2-0.2x+8=6

We move all terms to the left:

-0.01x^2-0.2x+8-(6)=0

We add all the numbers together, and all the variables

-0.01x^2-0.2x+2=0

a = -0.01; b = -0.2; c = +2;
Δ = b2-4ac
Δ = -0.22-4·(-0.01)·2
Δ = 0.12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{0.12}}{2*-0.01}=\frac{0.2-\sqrt{0.12}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{0.12}}{2*-0.01}=\frac{0.2+\sqrt{0.12}}{-0.02}
$